You are given two 0-indexed integer arrays player1 and player2, that represent the number of pins that player 1 and player 2 hit in a bowling game, respectively.

The bowling game consists of n turns, and the number of pins in each turn is exactly 10.

Assume a player hit x[i] pins in the ith turn. The value of the ith turn for the player is:

- 2 * x[i] if the player hit 10 pins in any of the previous two turns.

- Otherwise, it is x[i].

The score of the player is the sum of the values of their n turns.

Return

1 if the score of player 1 is more than the score of player 2,

2 if the score of player 2 is more than the score of player 1, and

0 in case of a draw.

Example 1:

Input: player1 = [4,10,7,9], player2 = [6,5,2,3]

Output: 1

Explanation: The score of player1 is 4 + 10 + 2*7 + 2*9 = 46.

The score of player2 is 6 + 5 + 2 + 3 = 16.

Score of player1 is more than the score of player2, so, player1 is the winner, and the answer is 1.

Example 2:

Input: player1 = [3,5,7,6], player2 = [8,10,10,2]

Output: 2

Explanation: The score of player1 is 3 + 5 + 7 + 6 = 21.

The score of player2 is 8 + 10 + 2*10 + 2*2 = 42.

Score of player2 is more than the score of player1, so, player2 is the winner, and the answer is 2.

Example 3:

Input: player1 = [2,3], player2 = [4,1]

Output: 0

Explanation: The score of player1 is 2 + 3 = 5

The score of player2 is 4 + 1 = 5

The score of player1 equals to the score of player2, so, there is a draw, and the answer is 0.

Constraints:

n == player1.length == player2.length

1 <= n <= 1000

0 <= player1[i], player2[i] <= 10

https://leetcode.com/problems/determine-the-winner-of-a-bowling-game/