There are M chocolate packets each packet can have variable number of chocolates. There are N students.
Distribute chocolate packets to students such that:
a: Each student gets 1 packet
b: The difference between number of chocolates in packet with maximum chocolates and packet with minimum chocolates given to the students is minimum.
package com.ideserve.saurabh.questions;
import java.util.Arrays;
public class DistributeChocolates {
public static void main(String[] args) {
int[] chocolatePackets = {12, 4, 7, 9, 2, 23, 25, 41 , 30, 40, 28, 42, 30, 44, 48, 43, 50};
distributeChocolates(chocolatePackets, 7);
}
public static void distributeChocolates(int[] chocolatePackets, int n) {
// If there are no chocolates or number of students is 0
if(chocolatePackets == null || chocolatePackets.length == 0 || n == 0) {
return;
}
// Sort the chocolatePackets
Arrays.sort(chocolatePackets);
System.out.println(Arrays.toString(chocolatePackets));
int m = chocolatePackets.length;
if(m < n) {
System.out.println("Number of students is more than number of packets. Cannot distribute!");
return;
}
int minDiff = chocolatePackets[m-1]; // Largest number of chocolates
int first = 0;
int last = 0;
int diff = 0;
for(int i = 0; i + n - 1 < m; i++) {
diff = chocolatePackets[i+n-1] - chocolatePackets[i];
if(diff < minDiff) {
minDiff = diff;
first = i;
last = i+n-1;
}
}
System.out.println(chocolatePackets[first] + " " + chocolatePackets[last]);
}
}
Time Complexity is O(n logn)